Na_2CO_3 cannot be used to identify which of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $Na_2CO_3$ is used to identify acid radicals by the evolution of $CO_2$ gas due to the reaction with stronger acids. $CO_3^{2-}$ ions cannot be id

Vedclass · Accepted Answer

$CO_3^{2-}$

Vedclass · Answer

(A) $Na_2CO_3$ is used to identify acid radicals by the evolution of $CO_2$ gas due to the reaction with stronger acids. $CO_3^{2-}$ ions cannot be identified using $Na_2CO_3$ because there is no reaction between the reagent and the analyte containing the same ion. $SO_3^{2-}$,$S^{2-}$,and $SO_4^{2-}$ salts of stronger acids react with $Na_2CO_3$ to evolve gases or form precipitates,allowing for their identification.

$Na_2CO_3$ cannot be used to identify which of the following ions?

Similar Questions

The incorrect statement in respect of the chromyl chloride test is:

Which of the following substances releases $SO_2$ gas upon reaction with dilute $H_2SO_4$?

Which of the following compounds will give a precipitate with $Pb(NO_3)_2$ but will not give a precipitate with $Ba(NO_3)_2$?

Which of the following gives the layer test?

Assertion $(A) :- Fe^{+3}$ is not used in the brown ring test for $NO_3^{-}$.
Reason $(R) :-$ Reduction of $NO_3^{-}$ takes place during the test.

Vedclass Test Series

Exam Paper Generator

Online Exam Module